2x^2=110

Solution for 2x^2=110 equation:

2x^2=110

We move all terms to the left:

2x^2-(110)=0

a = 2; b = 0; c = -110;
Δ = b2-4ac
Δ = 02-4·2·(-110)
Δ = 880
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{880}=\sqrt{16*55}=\sqrt{16}*\sqrt{55}=4\sqrt{55}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{55}}{2*2}=\frac{0-4\sqrt{55}}{4}
=-\frac{4\sqrt{55}}{4}
=-\sqrt{55}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{55}}{2*2}=\frac{0+4\sqrt{55}}{4}
=\frac{4\sqrt{55}}{4}
=\sqrt{55}
$